Question #205136

A card is chosen at random from a deck of 52 cards. It is then replaced and a second card is chosen. What is the probability of choosing a jack and then an eight?


Expert's answer

Р(getting jack on first chance) =452= \frac{4}{52}

P(getting an eight on second chance) =452= \frac{4}{52}

P(choosing a jack and then an eight) =452×452=\frac{4}{52} \times \frac{4}{52}

=1169= \frac{1}{169}


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