Answer to Question #205136 in Statistics and Probability for Shema Derrick

Question

A card is chosen at random from a deck of 52 cards. It is then replaced and a second card is chosen. What is the probability of choosing a jack and then an eight?

Answer 1

Р(getting jack on first chance) $= \frac{4}{52}$

P(getting an eight on second chance) $= \frac{4}{52}$

P(choosing a jack and then an eight) $=\frac{4}{52} \times \frac{4}{52}$

$= \frac{1}{169}$