Question

20% of a company’s employees are engineers and 20% are economists. 75% of the engineers and 50% of the economists hold a managerial position, while only 20% of non-engineers and non-economists have a similar position. What is the probability that an employee selected at random will be both an engineer and a manager?

Answer 1

Solution:

Notations:

En - person is engineer.

Ec - person in economist.

M - person is manager.

Given, $P(En)=0.2,P(Ec)=0.2$

Now, required probability = $P(M \cap En)=0.2\times 0.75=0.15=15\%$