A research was conducted to improve the safety plans in a factory. In this study, the accidental data of the factory for the last 50 weeks were compiled. These data are grouped into the frequency distribution as shown below:
Number of Accidents
Numbers of Weeks
0-5
8
5-10
22
10-15
10
15-20
8
20-25
2
Draw a histogram and calculate the average number of accidents per week.
Solution:
We need to compute the sample mean for these provided grouped data:
Now, we need to construct the midpoints based on the lower and upper limits of all the classes provided:
Now, with the midpoints, we need to multiply each midpoint for its corresponding frequency, as shown in the table below:
"\\begin{array}{ccl} \\bar X & = & \\displaystyle \\frac{1}{N} \\sum_{i=1}^k M_i \\cdot f_i \\\\\\\\ \\\\\\\\ & = & \\displaystyle \\frac{1}{50}\\left( 2.5 \\cdot 8+7.5 \\cdot 22+12.5 \\cdot 10+17.5 \\cdot 8+22.5 \\cdot 2 \\right) \\\\\\\\ \\\\\\\\ & = & \\displaystyle \\frac{495}{50} \\\\\\\\ \\\\\\\\ & = & 9.9 \\end{array}\n\u200b"
Therefore, based on the data provided, the sample mean for these grouped data is "\\bar X = 9.9"
Histogram
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