Question #203594

How many different ways can 3 bus drivers be selected from 11 bus drivers for a public transport service in a city


Expert's answer

N=11

n=3

Number of ways =N!n!(N−n)= \frac{N!}{n!(N-n)}

=11!3!(11−3)!=9906=165= \frac{11!}{3!(11-3)!} \\ = \frac{990}{6} \\ =165


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