How many different ways can 3 bus drivers be selected from 11 bus drivers for a public transport service in a city
N=11
n=3
Number of ways =N!n!(N−n)= \frac{N!}{n!(N-n)}=n!(N−n)N!
=11!3!(11−3)!=9906=165= \frac{11!}{3!(11-3)!} \\ = \frac{990}{6} \\ =165=3!(11−3)!11!=6990=165
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