Question

Suppose that for a given computer salesperson, the probability distribution of

 X= the number of systems sold in 1 week

Is given by the following:

X =1 P(x) =0.05 X= 2 P(x) = 0.10 X= 3 P(x)= 0.12 X= 4 P(x)=0.30 X= 5 P(x)= 0.30 X=6 P(x)= 0.11 X=7 P(x)= 0.01 X= 8 P(x)= 0.01

a. Find the mean value of x 

Answer 1

$\mu=1*0.05+2*0.10+3*0.12+4*0.30+5*0.30+6*0.11+7*0.01+8*0.01=$

$=4.12.$