Question #196704

A car dealership has both Electric and Internal Combustion Engine (ICE) vehicles available for sale. 30% of customers looking to purchase a new car are interested in Electric vehicles, while the rest want ICE vehicles. On a particular day, the dealership had 17 people coming in to purchase a new car. What is the probability that the number of people who are interested in an Electric vehicle is more than two standard deviations away from the mean value?


Expert's answer

Let X be the number of people.


XB(n,p)XB(17,0.30)X\sim B(n,p) \\ X\sim B(17,0.30)\\


Mean E(X)=np=17×0.3=5.1E(X)=np=17\times 0.3=5.1


Standard deviation-


s=np(1p)=17×0.3×(10.3)=1.8894s=\sqrt{np(1-p)}=\sqrt{17\times 0.3\times (1-0.3)}=1.8894


By using Normal approximation of Binomal distribution.


XN(μ=5.1,σ=1.8894)X\sim N(\mu=5.1,\sigma=1.8894)


Probability that the number of people who are interested in an Electric vehicle is more than two standard deviations away from the mean value is-


=P(X<μ2σ)+P(X>μ+2σ)=P(Z<2)+P(z>2)=0.0228+0.0228=0.0456=P(X<\mu-2\sigma)+P(X>\mu+2\sigma) \\[9pt] =P(Z<-2)+P(z>2) \\[9pt] =0.0228+0.0228\\[9pt]=0.0456


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