A sample of 50 socks is taken. What is the probability that the mean length of the sample is shorter than 18 cm?
n=50,μ=20n=50, \mu=20n=50,μ=20
SE=σn=10.550=10.57.07=1.48SE=\dfrac{\sigma}{\sqrt{n}}=\dfrac{10.5}{\sqrt{50}}=\dfrac{10.5}{7.07}=1.48SE=nσ=5010.5=7.0710.5=1.48
Probability that the mean length of the sample is shorter than 18 cm is-
P(X<18)=P(z<18−201.48P(X<18)=P(z<\dfrac{18-20}{1.48}P(X<18)=P(z<1.4818−20
P(X<18)=P(Z<−1.35)=0.0885P(X<18) = P(Z < -1.35)= 0.0885P(X<18)=P(Z<−1.35)=0.0885
THE PROBABILITY IS 0.0885
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