Answer to Question #196535 in Statistics and Probability for samuel

Question #196535

b.     Given the population 2,1,3,3,5,4,7 find the probability that a random sample of size 25, selected with replacement, will yield a sample mean greater than 3.7, but less than 4.3.



1
Expert's answer
2021-05-24T19:00:12-0400

Given population is- (2,1,3,3,5,7,4)


population mean μ=2+1+3+3+5+4+77=257=3.55\mu=\dfrac{2+1+3+3+5+4+7}{7}=\dfrac{25}{7}=3.55


Sample standard deviation-


s=(xμ)2ns=\sqrt{\dfrac{(x-\mu)^2}{n}}


=(1.55)2+(2.55)2+(0.55)2+(0.55)2+(1.45)2+(0.45)2+(3.45)271=\sqrt{\dfrac{(-1.55)^2+(-2.55)^2+(-0.55)^2+(-0.55)^2+(1.45)^2+(0.45)^2+(3.45)^2}{7-1}}


=23.71757=3.3882=1.9892=\sqrt{\dfrac{23.7175}{7}}=\sqrt{3.3882}=1.9892


Required Probability


P(3.7<x<4.3)=P(3.73.771.9892<z<4.33.771.9892)P(3.7<x<4.3)=P(\dfrac{3.7-3.77}{1.9892}<z<\dfrac{4.3-3.77}{1.9892})


=P(0.035<z<0.266)=0.11884=P(-0.035<z<0.266)\\[9pt]=0.11884


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