Given population is- (2,1,3,3,5,7,4)
population mean μ = 2 + 1 + 3 + 3 + 5 + 4 + 7 7 = 25 7 = 3.55 \mu=\dfrac{2+1+3+3+5+4+7}{7}=\dfrac{25}{7}=3.55 μ = 7 2 + 1 + 3 + 3 + 5 + 4 + 7 = 7 25 = 3.55
Sample standard deviation-
s = ( x − μ ) 2 n s=\sqrt{\dfrac{(x-\mu)^2}{n}} s = n ( x − μ ) 2
= ( − 1.55 ) 2 + ( − 2.55 ) 2 + ( − 0.55 ) 2 + ( − 0.55 ) 2 + ( 1.45 ) 2 + ( 0.45 ) 2 + ( 3.45 ) 2 7 − 1 =\sqrt{\dfrac{(-1.55)^2+(-2.55)^2+(-0.55)^2+(-0.55)^2+(1.45)^2+(0.45)^2+(3.45)^2}{7-1}} = 7 − 1 ( − 1.55 ) 2 + ( − 2.55 ) 2 + ( − 0.55 ) 2 + ( − 0.55 ) 2 + ( 1.45 ) 2 + ( 0.45 ) 2 + ( 3.45 ) 2
= 23.7175 7 = 3.3882 = 1.9892 =\sqrt{\dfrac{23.7175}{7}}=\sqrt{3.3882}=1.9892 = 7 23.7175 = 3.3882 = 1.9892
Required Probability
P ( 3.7 < x < 4.3 ) = P ( 3.7 − 3.77 1.9892 < z < 4.3 − 3.77 1.9892 ) P(3.7<x<4.3)=P(\dfrac{3.7-3.77}{1.9892}<z<\dfrac{4.3-3.77}{1.9892}) P ( 3.7 < x < 4.3 ) = P ( 1.9892 3.7 − 3.77 < z < 1.9892 4.3 − 3.77 )
= P ( − 0.035 < z < 0.266 ) = 0.11884 =P(-0.035<z<0.266)\\[9pt]=0.11884 = P ( − 0.035 < z < 0.266 ) = 0.11884
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