Answer to Question #195980 in Statistics and Probability for Zub

Question #195980

The latest M1 Macbook Air and Macbook Pro are available for sale at the Apple Store in Gulshan. 70% of the people who want to buy a new Macbook prefer the Macbook Air, while the rest prefer the Macbook Pro. Suppose 16 customers were randomly selected among those shopping for Macbooks on a specific day.

a) What is the mean value and the standard deviation of the number of people who want to purchase a Macbook Air? [2 marks]

b) What is the probability that the number of people who want a Macbook Air is more than two standard deviations away from the mean value? [4 marks]

c) The Apple Store only has 11 Macbook Airs and 14 Macbook Pros in stock. If the 16 people come in one after another to purchase a Macbook, what is the probability that all 16 will get the type of Macbook they want? [4 marks]


1
Expert's answer
2021-05-24T19:04:16-0400

a.) We have,

n=16n = 16

p=0.7p= 0.7

q=0.3q = 0.3

Mean value =np=16×0.7=11.2= np = 16 \times 0.7 = 11.2

Standard Deviation =npq=16×0.7×0.3=1.83= \sqrt{npq} = \sqrt{16 \times 0.7 \times 0.3} = 1.83


b.) The probability that the number of people who want a Macbook Air is more than two standard deviations away from the mean value


=P(X<μ2σ)+P(X>μ+2σ)= P(X<\mu-2\sigma)+ P(X>\mu+2\sigma)


=P(X<11.22(1.83))+P(X>11.2+2(1.83))= P(X<11.2-2(1.83))+P(X>11.2+2(1.83))


=P(X<7.54)+P(X>14.86)= P(X<7.54)+P(X>14.86)


=P(Z<7.5411.21.83)+P(Z>14.8611.21.83)= P(Z<\dfrac{7.54-11.2}{1.83})+P(Z>\dfrac{14.86-11.2}{1.83})


=P(Z<2)+P(Z>2)= P(Z<-2)+P(Z>2)


=0.0228+0.0228=0.0456= 0.0228+0.0228 = 0.0456


c.)  The probability that all 16 will get the type of Macbook they want =16C1627C16= \dfrac{^{16}C_{16}}{^{27}C_{16}}


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