Question #193145

one hundred pieces of a certain yarn were tested for strength, the mean value of the test results being 60N and their standard deviation 3N. calculate 95% confidence limits for the true mean strength of the yarn. if it was required to estimate the true mean correct to 1/2N . how many tests should be testes should be performed?


1
Expert's answer
2021-05-17T02:28:02-0400

Given, mean μ=60N,σ=3N\mu=60N,\sigma=3N

α=0.05\alpha=0.05


α2=0.025,Zα2=z0.025=1.96\dfrac{\alpha}{2}=0.025, Z_{\frac{\alpha}{2}}=z_{0.025}=1.96


95% confidence limit for true mean strength is given by-

=μ±Zα2σn=60±1.96×3100=60±0.588=(59.412,60.588)= \mu\pm Z_{\frac{\alpha}{2}}\dfrac{\sigma}{\sqrt{n}} \\ =60\pm 1.96\times \dfrac{3}{\sqrt{100}} \\ =60\pm 0.588 \\ =(59.412,60.588)


If we required to estimate the true mean correct to 12N\dfrac{1}{2}N , Then The number of test we would have to perform is two, The first is the t-test for independent sample and second test is p-value test.


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