Question #193140

Two balls are drawn in succession without replacement from an urn containing

2 green balls and 6 yellow balls. Let M be the random variable representing the

number of yellow balls.


1
Expert's answer
2021-05-17T02:19:03-0400

Total number of balls=8

Since Two balls are drawn at random and M denote the number of yellow balls.


So M cane be 0,1,2


Probability distribution of M is-


P(M=0)=6C0×2C28C2=128=0.0357P(M=1)=6C1×2C18C2=1228=0.4287P(M=2)=6C2×2C08C2=1528=0.5357P(M=0)= \dfrac{^6C_0\times ^2C_2}{^8C_2}=\dfrac{1}{28}=0.0357 \\[9pt] P(M=1)= \dfrac{^6C_1\times ^2C_1}{^8C_2}=\dfrac{12}{28}=0.4287 \\[9pt] P(M=2)= \dfrac{^6C_2\times ^2C_0}{^8C_2}=\dfrac{15}{28}=0.5357 \\[9pt]


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