Question #188558

Evelynn challenged Ahri and Kai'Sa to play a series of matches of darts. (with Akali eating her ramen and Seraphine being excited).


Here are the probabilities of each woman winning:

Kai'Sa: 50%; Evelynn: 30%; Ahri: 20%


If they play 6 games, Seraphine calculated that the probability of Ahri will win 1 game, Evelynn will win 2 games, and Kai'Sa will win 3 games is around Blank 1. (The probability is in decimal format with 4 decimal places.)


Akali is thoroughly impressed with Seraphine's arithmetic capabilities and decides to cook her some ramen as well.


1
Expert's answer
2021-05-07T14:22:40-0400

By condition,

p1=0.5,p2=0.3,p3=0.2{p_1} = 0.5,\,\,{p_2} = 0.3,\,\,{p_3} = 0.2

Using the polynomial scheme, we find  the probability of Ahri will win 1 game, Evelynn will win 2 games, and Kai'Sa will win 3 games:

P(3,2,1)=6!3!2!1!p13p22p1=45620.530.320.2=0.135P(3,2,1) = \frac{{6!}}{{3!2!1!}}p_1^3p_2^2{p_1} = \frac{{4 \cdot 5 \cdot 6}}{2} \cdot {0.5^3} \cdot {0.3^2} \cdot 0.2 = 0.135

Answer: P=0.135


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