If P(A) = 0.82, P(D) = 0.83, and P(D∩A) = 0.78, then P(A|D') is Blank 1 and P(D|A) is Blank 2.
4 Decimal Places
P(A)=0.82,P(D)=0.83,P(D∩A)=0.78P(A) = 0.82, P(D) = 0.83,P(D∩A) = 0.78P(A)=0.82,P(D)=0.83,P(D∩A)=0.78
P(A∣D)′=1−P(A∣D)=1−P(A∩D)P(D)=1−0.780.83=1−0.9397=0.06P(A|D)'=1-P(A|D)=1-\dfrac{P(A\cap D)}{P(D)}=1-\dfrac{0.78}{0.83}=1-0.9397=0.06P(A∣D)′=1−P(A∣D)=1−P(D)P(A∩D)=1−0.830.78=1−0.9397=0.06
P(D∣A)=D∩A)P(A)=0.780.82=0.9512P(D|A)=\dfrac{D\cap A)}{P(A)}=\dfrac{0.78}{0.82}=0.9512P(D∣A)=P(A)D∩A)=0.820.78=0.9512
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