If P(A) = 0.82, P(D) = 0.83, and P(D∩A) = 0.78, then P(A|D') is Blank 1 and P(D|A) is Blank 2.
4 Decimal Places
"P(A) = 0.82, P(D) = 0.83,P(D\u2229A) = 0.78"
"P(A|D)'=1-P(A|D)=1-\\dfrac{P(A\\cap D)}{P(D)}=1-\\dfrac{0.78}{0.83}=1-0.9397=0.06"
"P(D|A)=\\dfrac{D\\cap A)}{P(A)}=\\dfrac{0.78}{0.82}=0.9512"
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