The number of all possible outcomes is C(52,6) because we take 6 cards from 52 cards deck.
a) we want to have 2, 3, or 4 kings and any other cards in the rest of 6 cards.
P(A)=C(52,6)C(4,2)⋅C(50,4)+C(52,6)C(4,3)⋅C(49,3)+C(52,6)C(4,4)⋅C(48,2)=203585206⋅230300+4⋅18424+1⋅1128=203585201456624=0.0715
b) none are aces means that we can select any from 48 cards (52 - 4 aces)
P(B)=C(52,6)C(48,6)=2035852012271512=0.603
c) P(C) = 1 - P(5 or 6 black cards)
P(C)=1−C(52,6)C(26,5)⋅C(26,1)−C(52,6)C(26,6)=1−0.084−0.011=0.905
d) P(D)=C(52,6)C(26,6)=0.0113
Comments