Let p denote the probability of females p=0.6
q=1−p=0.4
(a) Probability that a class of 10 students will have exactly four females.
=10C4p4q6
=10C4(0.6)4(0.4)6
=0.1114
(b) Probability that a class of 10 students will contain five,six or seven females.
=10C5p5q5+10C6p6q4+10C7p7q3
=10C5(0.6)5(0.4)5+10C6(0.6)6(0.4)4+10C7(0.6)7(0.4)3=0.2006+0.2508+0.2149=0.6663
(c) Probability that at least five students in a class of 10 will be female
=10C5p5q5+10C6p6q4+10C7p7q3+10C8p8q2+10C9p9q+10C10p10
=10C5(0.6)5(0.4)5+10C6(0.6)6(0.4)4+10C7(0.6)7(0.4)3+10C8(0.6)8(0.4)2+10C9(0.6)9(0.4)+10C10(0.6)10=0.2006+0.2508+0.2149+0.1209+0.0403+0.00604=0.83354
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