If the measure of systolic blood pressure is normally distributed with a mean of 120 and a standard deviation of 10, find the probability that a randomly selected person will have a systolic blood pressure below 130. Assume systolic blood pressure is normally distributed.
Solution:
Given, "\\mu=130,\\sigma=10"
"z=\\dfrac{X-\\mu }{\\sigma}"
"P(X<130)=P(z<\\dfrac{130-120 }{10})"
"=P(z<1)=0.84134" [Using z-score table]
Comments
Leave a comment