Question #166932

The accompanying table describes results from groups of 10 births from 10 different sets of parents. The random variable x represents the number of girls among 10 children. Use the range rule of thumb to determine whether 1 girl in 10 births is a significantly low number of girls.

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x P(x)

0 0.005

1 0.018

2 0.044

3 0.117

4 0.198

5 0.245

6 0.206

7 0.114

8 0.037

9 0.015

10 0.001


Expert's answer

Solution

Range rule of thumb states that the range is approximately four times the standard deviation.





SD(x)=∑x2P(x)−(∑xP(x))2SD(x) = \sqrt{ \sum {x^2P(x)} - {(\sum {xP(x)}}) ^2}

=27.225−4.9492=1.652997= \sqrt {27.225 - {4.949}^2} =1.652997

Range=4SD(x)Range = 4 SD(x)

=4(1.652997)=6.611988=4(1.652997)=6.611988


But

Range=max. value−min. valueRange = max. \space value - min. \space value

Max.=xˉ+2SD(x)Max. = \bar{x} + 2SD(x)=4.949+2(1.652997)=8.254994=4.949+2(1.652997) =8.254994

Min=xˉ−2SD(x)Min = \bar {x} - 2SD(x)=4.949−2(1.652997)=1.643=4.949-2(1.652997) =1.643

Since

Maximum≈9 Maximum \approx 9 \spaceand Minimum≈2Minimum \approx 2


1 girl in 10 births is a significantly low number of girls



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