a certain type of battery has a mean shelf life of 600 days with a standard deviation of 28 days
Q:What is the probability that the shelf life of the battery is over 630 days?
Mean(μ\muμ )= 600
Standard deviation(σ\sigmaσ )= 28
Normal distribution formula⇒z=xˉ−μσ\Rightarrow z=\dfrac{\bar x-\mu}{\sigma}⇒z=σxˉ−μ
⇒z=630−60028\Rightarrow z=\dfrac{630-600}{28}⇒z=28630−600
⇒z=1.071\Rightarrow z=1.071⇒z=1.071
P(z>1.071)=0.5−0.3577=0.1423P(z>1.071)= 0.5-0.3577=0.1423P(z>1.071)=0.5−0.3577=0.1423
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