Answer to Question #163279 in Statistics and Probability for udfs

Question

Jaxson is a great free throw shooter. Over the last year he has made 88

%

88%

 of his free throws. If his probability stays consistent, what is the probability he will make his next three free throws? Show complete work on your worksheet!

Answer 1

$n = 3 \\ p = 0.88 \\ (1 - p) = 0.12 \\ x = 3$

As per binomial distribution formula

$P(X = x) = nC^x \times p^x \times (1 - p)^{n - x}$

We need to calculate P(X = 3)

$P(X = 3) = 3C^3 \times 0.88^3 \times 0.12^0 \\ P(X = 3) = 0.6814$