Answer to Question #154308 in Statistics and Probability for Ali Ahmed

Question #154308

To compare customer satisfaction levels of two competing ice cream companies, 8 customers of Company 1 and 5 customers of Company 2 ware randomly selected and were asked to rate their ice creams on a five-point scale, with 1 being least satisfied and 5 most satisfied. The survey results are summarized in the following table: Company 1 Company 2 ๐‘›1=8 ๐‘›2=5 ๐‘‹1 ฬ…ฬ…ฬ…ฬ…=3.21 ๐‘‹2 ฬ…ฬ…ฬ…ฬ…=2.22 ๐‘†1= 0.31 ๐‘†2= 0. 21 By assuming both equal variances and unequal variances: a. Construct an interval estimate at 95ยฐ/ confidence interval for difference of means of two ice cream companies.


1
Expert's answer
2021-01-13T16:57:15-0500

We have that

n1 = 8

"\\bar x_1 = 3.21"

s1 = 0.31

n2 = 5

"\\bar x_2 = 2.22"

s2 = 0.21


Assuming both variances are equal:

Since samples are less than 30 in this problem we are dealing withย t-distirbution with n1ย + n2ย โ€“ 2 = 8 + 5 โ€“ 2 = 11 degrees of freedom.

The table t-value for a 95% confidence interval with 25 df is t0.025, 11 = 2.201

The formula forย a 95% confidence interval for the difference of two population means:


"(\\bar x_1-\\bar x_2)\\pm t_{0.025, 11}s_p\\sqrt{\\frac{1}{n_1}+\\frac{1}{n_2}}"

where

"s_p=\\sqrt{\\frac{s_1^2(n_1-1)+s_2^2(n_2-1)}{n_1+n_2-2}}"

"s_p=\\sqrt{\\frac{0.31^2\\cdot7+0.21^2\\cdot4}{8+5-2}}=0.28"

Confidence interval:

"(3.21-2.22)\\pm2.201\\cdot0.28\\sqrt{\\frac{1}{8}+\\frac{1}{5}}=0.99\\pm0.35"

We are 95% confident that the difference in the two population means is between 0.64 and 1.34. Zero is not in this interval so there is a significant difference of means of two ice cream companies.


Constructing a confidence interval for the difference of means when both variances are not equal:


"(\\bar x_1-\\bar x_2)\\pm t\\sqrt{\\frac{s_1^2}{n_1}+\\frac{s_2^2}{n_2}}"

where df is the smaller of n1โ€“1 and n2โ€“1

df = min(8-1, 5-1)=4

Therefore the table t-value for a 95% confidence interval with 4 df is t0.025, 4 = 2.776

"(3.21-2.22)\\pm 2.776\\sqrt{\\frac{0.31^2}{8}+\\frac{0.21^2}{5}}=0.99\\pm 0.4"

We are 95% confident that the difference in the two population means is between 0.59 and 1.39. Zero is not in this interval so there is a significant difference of means of two ice cream companies.


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