Suppose x is a normal random variable with mean 60 and standard deviation 2. A z score was calculated for a number, and the z score is 3.4. What is x
x=μ+zσ=60+3.4∗2=66.8x = \mu+z\sigma=60+3.4*2=66.8x=μ+zσ=60+3.4∗2=66.8
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