The American Red Cross says that about 25% of the population has Type B blood. A blood drive is being held at your institute. Suppose that you have selected 20 blood donors in a random way. The probability that exactly 2 of the blood donors have Type B blood is
Given: p = 0.25; x = 2; n = 20
"b(n,p,x) = \\binom{n}{x}*p^x* {\\lparen1-p\\rparen}^{\\lparen n-x\\rparen}"
Here "\\binom{n}{x}\\equiv C^x_n = \\frac{n!}{x!(n-x)!}"
Then "b(20,0.25,2) = \\frac{20!}{2!(20-2)!}*0.25^2*(1-0.25)^{20-2} ="
"= \\frac{19*20}{2}*0.0625*0.75^{18} \\approx 190*0.625* 0.0056377 \\approx 0.066947"
Answer "b \\approx 0.066947"
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