1. The random variable X has the binomial distribution: X∼Bin(n,p)
p(X=x)=(xn)px(1−p)n−x Given p=0.25,n=20
X∼Bin(20,0.25)
p(X=x)=(x20)(0.25)x(1−0.25)20−x 2.
p(X=15)=(1520)(0.25)15(1−0.25)20−15
=5!(20−15)!20!(0.25)15(0.75)5
≈0.0000034265 The probability so that X is equal to 15 is approximately 3.4265×10−6
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