Let "X=" the mark of student in a mathematical contest: "X\\sim N(\\mu,\\sigma^2\/n)." Then
"Z=\\dfrac{X-\\mu}{\\sigma\/\\sqrt{n}}\\sim N(0,1)"
Given "\\mu=60, \\sigma^2=100, n=3"
"=1-P(Z<\\dfrac{75-70}{10\/\\sqrt{3}})"
"\\approx1-P(Z<0.866)"
"\\approx1-0.806762=0.193238"
The probability that a team is rewarded is "0.193238."
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