Question

𝑷(𝑿 = 𝒙)=k/x+1;where x = 1,2,3

Answer 1

I assume that the question asks for the value of k.

$\sum P(xi)=1$

Thus $\frac{k}{2}+ \frac{k}{3}+ \frac{k}{4}=1$

$\frac{6k+4k+3k}{12}=1$

$\frac{13k}{12}=1$

$K=\frac{12}{13}$