π·(πΏ = π)=k/x+1;where x = 1,2,3
I assume that the question asks for the value of k.
"\\sum P(xi)=1"
Thus "\\frac{k}{2}+ \\frac{k}{3}+ \\frac{k}{4}=1"
"\\frac{6k+4k+3k}{12}=1"
"\\frac{13k}{12}=1"
"K=\\frac{12}{13}"
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