μ=50
σ=16
n=600
a) P(X<55)=P(Z<σ55−μ)=P(Z<1655−50)=P(Z<0.3125)=0.6217
wich is 62.17%
b) P(X>52)=P(Z>1652−50)=P(Z>0.125)=1−P(Z<0.125)=
=1−0.5478=0.4522
600⋅0.4522=271
Answer:
a) 62.17% of students with weights lower than 55 kilograms
b) 271 students have weights exceeding 52 kilograms
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