"(a)P(x=4)=C_{4}^{12}(0.32)^{4}(0.68)^{12-4}\\approx 0.237\\\\\n(b)P(x>14)=P(x=15)+P(x=16)\\\\\n=C_{15}^{16}(0.68)^{15}(0.32)^{16-15}+C_{16}^{16}(0.68)^{16}(0.32)^{16-16}\\\\\n\\approx 0.0178\\\\\n(c)P(x\\geq 2)=1-P(x<2)\\\\\n=1-[P(x=0)+P(x=1)]\\\\\n=1-[C_{0}^{20}(0.32)^{0}(0.68)^{20-0}\\\\+C_{1}^{20}(0.32)^{1}(0.68)^{20-1}]\\\\\n\\approx 0.995 \\\\"
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