(a)P(x=4)=C412(0.32)4(0.68)12−4≈0.237(b)P(x>14)=P(x=15)+P(x=16)=C1516(0.68)15(0.32)16−15+C1616(0.68)16(0.32)16−16≈0.0178(c)P(x≥2)=1−P(x<2)=1−[P(x=0)+P(x=1)]=1−[C020(0.32)0(0.68)20−0+C120(0.32)1(0.68)20−1]≈0.995(a)P(x=4)=C_{4}^{12}(0.32)^{4}(0.68)^{12-4}\approx 0.237\\ (b)P(x>14)=P(x=15)+P(x=16)\\ =C_{15}^{16}(0.68)^{15}(0.32)^{16-15}+C_{16}^{16}(0.68)^{16}(0.32)^{16-16}\\ \approx 0.0178\\ (c)P(x\geq 2)=1-P(x<2)\\ =1-[P(x=0)+P(x=1)]\\ =1-[C_{0}^{20}(0.32)^{0}(0.68)^{20-0}\\+C_{1}^{20}(0.32)^{1}(0.68)^{20-1}]\\ \approx 0.995 \\(a)P(x=4)=C412(0.32)4(0.68)12−4≈0.237(b)P(x>14)=P(x=15)+P(x=16)=C1516(0.68)15(0.32)16−15+C1616(0.68)16(0.32)16−16≈0.0178(c)P(x≥2)=1−P(x<2)=1−[P(x=0)+P(x=1)]=1−[C020(0.32)0(0.68)20−0+C120(0.32)1(0.68)20−1]≈0.995
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