Question #145201

A survey was taken among college students as to how many minutes they play a newly released online game, Genshin Impact, per day. Using UNGROUPED statistical analysis, calculate the following:

a.) Mean, Median, and Mode,

b.) Variance and Standard Deviation.
Time(Mins)
174
300
204
185
326
158
300
280
210
194
345
347
339
300
187
329
184
275
180
136

Expert's answer

Given data in ascending order:

136,158, 174, 180, 184, 185, 187, 194, 204, 210, 275, 280, 300, 300, 300, 326, 329, 339, 345, 347

n=20


Mean:

xˉ=∑xn=136+158+174+180+184+185+187+194+204+210+275+280+300+300+300+326+329+339+345+34720=247.65\bar x=\frac{\sum x}{n}=\frac{136+158+174+180+184+185+187+194+204+210+275+280+300+300+300+326+329+339+345+347}{20}=247.65


Median is a value separating the higher half from the lower half of a data sample, thus median is the mean of the middle two numbers:

median=210+2752=242.5median = \frac{210+275}{2}=242.5


Mode is the most frequent value in data set:

mode = 300


Variance:

s2=∑(x−xˉ)2n−1s^2=\frac{\sum{(x-\bar x)^2}}{n-1}

s2=(136−247.65)2+...+(347−247.65)220−1=5201.29s^2=\frac{(136-247.65)^2+...+(347-247.65)^2}{20-1}=5201.29


Standard deviation:

s=∑(x−xˉ)2n−1s=\sqrt{\frac{\sum{(x-\bar x)^2}}{n-1}} or s=variances=\sqrt{variance}

s=5201.29=72.12s=\sqrt{5201.29}=72.12


Answer:

a) mean = 247.65, median = 242.5, mode = 300

b) variance = 5201.29, standard deviation = 72.12


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