Let "X=" IQ score: "X\\sim N(\\mu, \\sigma^2)"
Then "Z=\\dfrac{X-\\mu}{\\sigma}\\sim N(0, 1)"
Given "\\mu=100, \\sigma=15"
If 20% of your classmates higher than you , what is your IQ?
"P(Z\\leq\\dfrac{x-100}{15})=0.8"
"\\dfrac{x-100}{15}\\approx0.841621"
"x\\approx112.6"
My score was 112.6.
If my IQ is 85, what percentage of people have a higher IQ than I?
If my IQ is 85, approximately 84% of people have a higher IQ than I.
Comments
Leave a comment