solution
Probability of success p=0.2
Let X be the number of sales made out of the 2 attempts.
P(X=x)= nCx∗px∗(1−p)n−x
Part i) making no sales
P(X=0)
= 2C0∗0.20∗(0.8)2=0.64
answer: 0.64
Part ii) making more than 1 sale
P(X>1)=P(X=2)
= 2C2∗0.22∗(0.8)0=0.04
answer: 0.04
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