We need to construct the 99% confidence interval for the population mean
μ. The following information is provided:
sample mean "\\overline{X}=900\\\\s=30\\\\N=100"
since sample size is larger and normally distributed , we use Z confidence interval .
The critical value for α=0.01 is "z_c = z_{1-\\alpha\/2} = 2.576"
.The corresponding confidence interval is computed as shown below:
"\\begin{array}{ccl} CI= \\displaystyle \\left( \\bar X - z_c \\times \\frac{\\sigma}{\\sqrt{n}}, \\bar X + z_c \\times \\frac{\\sigma}{\\sqrt{n}} \\right) \\\\ \\\\ \\displaystyle= \\left( 900 - 2.576 \\frac{30}{\\sqrt{100}} , 900 + 2.576 \\frac{30}{\\sqrt{100}} \\right) \\\\ \\\\ = (892.26, 907.74) \\end{array}\n\n\n\n\n\n\n\n\n\u200b"
Answer: option 5
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