Question #134413

2. Given P(E) = 0.25, P(F) = 0.6, and P(E ∪ F) = 0.7.

Find:


a. What is P(E ∩ F)?

b. Are event E and event F mutually exclusive? Justify your answer.

c. Are event E and event F independent? Justify your answer.


1
Expert's answer
2020-09-22T16:22:39-0400

P(EF)=P(E)+P(F)P(EF)P(E \cup F) = P(E) + P(F) - P(E \cap F). From here we have:

a. P(EF)=P(E)+P(F)P(EF)=0.25+0.60.7=0.15P(E \cap F) = P(E) + P(F) - P(E \cup F) = 0.25+0.6-0.7 =0.15

b. If events are mutually exclusive, then P(EF)=0P(E \cap F) =0. As we see from (a), P(EF)0P(E \cap F) \neq 0, therefore these events are not mutually exclusive.

c. If events are independent, then P(EF)=P(E)P(F)P(E \cap F) = P(E) \cdot P(F). Let's check this.

P(E)P(F)=0.250.6=0.15P(E) \cdot P(F) = 0.25 \cdot0.6 = 0.15 and P(EF)=0.15P(E \cap F)= 0.15.

Indeed, P(EF)=P(E)P(F)P(E \cap F) = P(E) \cdot P(F), so these events are independent.


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