Question #134355

Consider a pair of ten sided dice. (a) what is the probability of rolling nines for both dice. (b) what is the probability that the sum of the dice is 18?

Expert's answer

Solution to a :

Probability of rolling 9 and 9:


P(x=9andx=9)=p(x=9)P(x=9)P(x=9 and x=9)= p(x=9) * P(x=9)

And

P(x=9)=110P(x=9) = {1 \over 10}

Therefore ;

=(110)(110)=1100= ({1 \over 10})({1 \over 10}) = { 1 \over 100}

Answer: 0.01


Solution to b

Probability sum is 18:


=P(9and9)orP(10and8)orP(8and10)=P(9 and 9) or P(10 and 8) or P(8 and 10)

=P(x=9)P(x=9)+= P(x=9) * P(x=9) +


P(x=10)P(x=8)+P(x=8)P(x=10)P(x=10) * P(x=8) + P(x=8)*P (x=10)


=(110)(110)+(110)(110)+(110)(110)= ( {1 \over 10})( {1 \over 10}) + ({1 \over 10}) ({1 \over 10}) + ( {1 \over 10})( {1 \over 10})

=1100+1100+1100=3100={1 \over 100} + {1 \over 100} + {1 \over 100} = {3 \over 100}

Answer: 0.03

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