Question #134355
Consider a pair of ten sided dice. (a) what is the probability of rolling nines for both dice. (b) what is the probability that the sum of the dice is 18?
1
Expert's answer
2020-09-22T16:02:14-0400

Solution to a :

Probability of rolling 9 and 9:


P(x=9andx=9)=p(x=9)P(x=9)P(x=9 and x=9)= p(x=9) * P(x=9)

And

P(x=9)=110P(x=9) = {1 \over 10}

Therefore ;

=(110)(110)=1100= ({1 \over 10})({1 \over 10}) = { 1 \over 100}

Answer: 0.01


Solution to b

Probability sum is 18:


=P(9and9)orP(10and8)orP(8and10)=P(9 and 9) or P(10 and 8) or P(8 and 10)

=P(x=9)P(x=9)+= P(x=9) * P(x=9) +


P(x=10)P(x=8)+P(x=8)P(x=10)P(x=10) * P(x=8) + P(x=8)*P (x=10)


=(110)(110)+(110)(110)+(110)(110)= ( {1 \over 10})( {1 \over 10}) + ({1 \over 10}) ({1 \over 10}) + ( {1 \over 10})( {1 \over 10})

=1100+1100+1100=3100={1 \over 100} + {1 \over 100} + {1 \over 100} = {3 \over 100}

Answer: 0.03

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