Answer to Question #131905 in Statistics and Probability for aman

Question #131905
suppose that an airplane engine will fail, when in flight, with probability 1−p independently from engine to engine; suppose that the airplane will make a successful flight if at least 50 percent of its engines remain operativ
1
Expert's answer
2020-09-07T15:42:19-0400

Here given,

engine fail probabilityP(F) = 1−p independently from engine to engine.

engine success probability P(S) = 1-(1-p)

= p

There no question specified . I think a question is like

'For what values of p is a four-engine plane preferable to a two-engine plane?'


For making four engine airplane success at least 2 engine of them should be success.


so, probability = (4C2)p2(1p)2+(4C3)p3(1p)1+(4C1)p4(1p)0=6p2(1p)2+4p3(1p)+4p4(4C2)p^2(1-p)^2 + (4C3)p^3(1-p)^1 + (4C1)p^4(1-p)^0 = 6p^2(1-p)^2+4p^3(1-p) + 4p^4


required Probability for 2 engine airplane success at least 1 engine should success

= (2C1)p1(1p)1+(2C2)p2(1p)0(2C1)p^1(1-p)^1 + (2C2)p^2(1-p)^0

=2(p)(1-p) + p2

The four-engine plane is safe if:


 6p2(1p)2+4p3(1p)+4p42(p)(1p)+p26p^2(1-p)^2+4p^3(1-p) + 4p^4 \geq 2(p)(1-p) + p^2


6p(1p)+4p(1p)+p2p6 p(1− p) + 4 p (1− p) + p ≥ 2 − p


3p38p2+7p20or(p1)2(3p2)03p^3-8p^2+7p-2 \geq0 \,or \, ( p-1)^2 (3p-2) \geq 0


3p20so,p2/33p-2 \geq 0 \,so, \, p \geq2/3



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