Here given,
engine fail probabilityP(F) = 1−p independently from engine to engine.
engine success probability P(S) = 1-(1-p)
= p
There no question specified . I think a question is like
'For what values of p is a four-engine plane preferable to a two-engine plane?'
For making four engine airplane success at least 2 engine of them should be success.
so, probability = "(4C2)p^2(1-p)^2 + (4C3)p^3(1-p)^1 + (4C1)p^4(1-p)^0\n\n\n\n= 6p^2(1-p)^2+4p^3(1-p) + 4p^4"
required Probability for 2 engine airplane success at least 1 engine should success
= "(2C1)p^1(1-p)^1 + (2C2)p^2(1-p)^0"
=2(p)(1-p) + p2
The four-engine plane is safe if:
"6p^2(1-p)^2+4p^3(1-p) + 4p^4 \\geq 2(p)(1-p) + p^2"
"6 p(1\u2212 p) + 4 p (1\u2212 p) + p \u2265 2 \u2212 p"
"3p^3-8p^2+7p-2 \\geq0 \\,or \\, ( p-1)^2 (3p-2) \\geq 0"
"3p-2 \\geq 0 \n\\,so, \\, p \\geq2\/3"
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