In this case, we have been given that out of 4 tosses the first toss is a head.
So now we need to obtain 2 more heads in the remaining 3 tosses.
The number of heads can be modeled as a binomial distribution.
Assuming that the coin is fair the probability of getting a head, p = 0.5.
Thus number of remaining tosses, n = 3
We want probability that X = 2 (X being the random variable denoting the number of heads obtained in the experiment)
We know that , if X~Bin(n,p), then P(X = x) = (nCx).px(1-p)(n-x)
"\\therefore P(X = 2) =(3C2)*(0.5)^2*(1-0.5)^{(3-2)}"
"\\therefore P(X = 2) = 0.375"
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