Question #128157
Close to 15 hospitals in Maharashtra has to be completely or partially shut down after
many of their staff were quarantined following exposure to COVID-19 patients. The
number x of medical staff entering the hospitals treating COVID-19 patients on any
week has a Poisson probability distribution with average equal to 5 staff per week.
(a) What is the probability that the number of staff entering the hospital on a particular
week is two
(b) Is it likely that x will exceed 10? Substantiate your answer.
1
Expert's answer
2020-08-03T19:13:30-0400

(a) Poisson probability


P(X=x)=eμμxx!P(X=x)=\dfrac{e^{-\mu}\cdot \mu^x}{x!}

Given μ=5\mu=5


P(X=2)=e5522!0.084224P(X=2)=\dfrac{e^{-5}\cdot 5^2}{2!}\approx0.084224

(b)


P(X>10)=1P(X10)=P(X>10)=1-P(X\leq 10)==1P(X=0)P(X=1)P(X=2)=1-P(X=0)-P(X=1)-P(X=2)-P(X=3)P(X=4)P(X=5)-P(X=3)-P(X=4)-P(X=5)-P(X=6)P(X=7)P(X=8)-P(X=6)-P(X=7)-P(X=8)-P(X=9)P(X=10)0.0137-P(X=9)-P(X=10)\approx0.0137

We note P(X>10)=0.0137<0.05.P(X>10)=0.0137<0.05. We consume that the probability P(X>10)=0.0137P(X>10)=0.0137 is small, which indicates that the event is unlikely to occur by chance and thus it is not likely that XX will exceed 10.



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