Answer to Question #128080 in Statistics and Probability for ysabe castro

Question #128080
Given P(E) = 0.25, P(F) = 0.6, and P(E ∪ F) = 0.7.
Find:
1
Expert's answer
2020-08-03T18:12:53-0400
"P(E\\cup F)=P(E)+P(F)-P(E\\cap F)"

"P(E\\cap F)=P(E)+P(F)-P(E\\cup F)="

"=0.25+0.6-0.7=0.15"

Since "P(E\\cap F)\\not =0," then event "E" and event "F" are not mutually exclusive.



"P(E)\\cdot P(F)=0.25\\cdot0.6=0.15=P(E\\cap F)"

Event "E" and event "F" are independent.



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Comments

andy
15.03.21, 18:32

Event E and event F are independent

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