Let A = the event that the student takes technology
and B = the event that the student takes foreign language
"\\therefore" A "\\cap" B is the event that the student takes both technology and foreign language
and A | B is the event that the student takes both technology given that the student takes foreign language
Since, 60% of the students take a foreign language class and 20% of the students take both foreign language and technology
Then we have, P(B) = 60% = 0.6 and P(A "\\cap" B) = 20% = 0.2
Now we have,
P(A | B) = "\\frac{P(A\\cap B)}{P(B)}" = "\\frac{0.2}{0.6}" = 0.33
Answer: The probability that a student takes technology given that the student takes foreign language is 0.33.
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