The probability that a bike will meet safety standards is 212=16\frac {2}{12}=\frac {1}{6}122=61
P(X=x)=(nx)pxqn−xP(X=x) ={n\choose x} p^xq^{n-x}P(X=x)=(xn)pxqn−x
P(X≥2)=∑i=26(6x)(16)x(56)6−xP(X \ge 2)=\sum_{i=2}^6 {6 \choose x} (\frac {1}{6})^x(\frac {5}{6})^{6-x}P(X≥2)=∑i=26(x6)(61)x(65)6−x
=0.2632
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