To find : confidence interval for 95%
Since population sd is unknown and it is normally distributed , we use t confidence interval
Formula:
"\\left [\\overline{x } -t^{^{*}}\\frac{s}{\\sqrt{n}},\\overline{x } +t^{^{*}}\\frac{s}{\\sqrt{n}}\\right ]"
From given data
"\\overline{x }= 9.85,\ns=1.572,t^{*}=" 3.182
(The number of degrees of freedom are df = 4 - 1 = 3 and the significance level is alpha = 0.05)
calculation:
"{\\left [9.85 -3.182*\\frac{1.572}{\\sqrt{4}},9.85 +3.182*\\frac{1.572}{\\sqrt{4}}\\right ]}"
[7.349,12.351] is the required solution.
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