P=(P(C).P(defective∣С))/((P(A).P(defective∣A)+(P(B).P(defective∣B)+(P(C).P(defective∣С))
P(TechZone )=0.30
P(Advance Electronics)=0.25
P(PSP )=0.18
P(TechParts )=0.32
P(defective∣TechZone )=0.03
P(defective∣Advance Electronics)=0.04
P(defective∣PSP )=0.07
P(defective∣TechParts )=0.065
a)P=P(TechZone )*P(defective∣TechZone )+P(Advance Electronics)*P(defective∣Advance Electronics)+P(PSP )*P(defective∣PSP )+P(TechParts )*P(defective∣TechParts )=0.30 *0.03+0.25*0.04+0.18 *0.07+0.32 *0.065=0.0524
b)P=P(TechZone )*P(defective∣TechZone )/(P(TechZone )*P(defective∣TechZone )+P(Advance Electronics)*P(defective∣Advance Electronics)+P(PSP )*P(defective∣PSP )+P(TechParts )*P(defective∣TechParts ))=0.009/0.0524=0.17
c)P=P(TechParts )*P(defective∣TechParts )/(P(TechZone )*P(defective∣TechZone )+P(Advance Electronics)*P(defective∣Advance Electronics)+P(PSP )*P(defective∣PSP )+P(TechParts )*P(defective∣TechParts ))=0.0208/0.0524=0.3969
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Dear Ali khan, please use the panel for submitting new questions.
In a Internee program at Airline Company, 60 percent of the internees are female and 40 percent male. 80 percent of the females are business students, and 65 percent of the males are business students. a) An internee is selected at random. What is the probability that the person selected is a female who is not a business student? b) Are gender and field of study, independent in this case? Why?
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