Assuming all of the 5 buses are available , in the start location and the end destinatioin troughout the time period of the journey.
The probability of man selecting one of the 5 buses for the trip=P(x)
selecting one of four other buses for the return trip P(y)
"P(x)=\\frac{1}{5}\\\\\nP(y)=\\frac{^4C_1}{^5C_1}=\\frac{4}{5}\\\\"
Therefore the probability that,A man can go by any of the 5 buses and will return by any of the remaining 4 buses is given by,
"P=P(x)\\times P(y)=\\frac{1}{5} \\times \\frac{4}{5}=\\frac{4}{25}"
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