"\\def\\arraystretch{1.5}\n \\begin{array}{c:c:c:c:c:c:c:c}\n x & 2 & 1 & 4 & 5 & 3 & 6\\text{ and more} & 0 \\\\ \\hline\n f(x) & 0.17 & 0.23 & 0.08 & 0.04 & 0.14 & 0.02 & ? \\\\\n \n\\end{array}"
a) "P(X=0)" - the probability, that there will be no letter for the next hour.
To find "P(X=0)" we can use the fact that "\\sum P(X=x) =1" .
We have: "0.17+0.23+0.08+0.04+0.14+0.02+P(X=0)=1"
"P( X=0)= 0.32"
Answer: 0.32
b) "F(x)=P(X\\leq x)=P(X=0)+P(X=1)+\u2026+P(X=x)"
Using this formula, we have:
"\\def\\arraystretch{1.5}\n \\begin{array}{c:c:c:c:c:c:c:c}\n x & 0 & 1 & 2 & 3 & 4 &5& 6\\text{ and more} \\\\ \\hline\n F(x) & 0.32 & 0.55 & 0.72 & 0.86 & 0.94 & 0.98 & 1 \\\\\n \n\\end{array}"
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