Answer to Question #105393 in Statistics and Probability for Evan

Question

3) Our class is creating a new academic team, the Data Managers. The team will have 4 members to perform different tasks: collector, analyzer, grapher, and recorder. 10 people in class want to be on the team, so we pick a random team out of the 10.
A) If exactly 4 boys volunteer, what is the probability that the team is all boys or no boys? Evaluate your answer.
B) What is the probability that Student 1 and Student 2 are on the team? Evaluate your answer.
C) With two teacher coaches, the team of four takes a picture (6 people in picture). What is the probability that the teachers are together in the picture? Evaluate your answer.

Answer 1

A) If exactly 4 boys volunteer, what is the probability that the team is all boys or no boys? 

$$P(all\ four\ boys\ or\ no\ boys)=$$

$$=P(all\ four\ boys)+P(no\ boys)=$$

$$={\dbinom{4}{4}\dbinom{10-4}{4-4} \over \dbinom{10}{4}}+{\dbinom{4}{0}\dbinom{10-4}{4-0} \over \dbinom{10}{4}}=$$

$$={1(1) \over \dfrac{10!}{4!(10-4)!}}+{1\cdot\dfrac{6!}{4!(6-4)!} \over \dfrac{10!}{4!(10-4)!}}=$$ $$={1 \over 210}+{15 \over 210}={8 \over 105}$$

B) What is the probability that Student 1 and Student 2 are on the team?

$$P(Student1\ \&\ Student2 )={\dbinom{1}{1}\dbinom{10-2}{4-2} \over \dbinom{10}{4}}=$$ $$={1\cdot\dfrac{8!}{2!(8-2)!} \over \dfrac{10!}{4!(10-4)!}}={28 \over 210}={2 \over 15}$$

C) With two teacher coaches, the team of four takes a picture (6 people in picture). What is the probability that the teachers are together in the picture? 

Consider two teacher coaches as one unit.

$$P(teachers\ are \ together)={2!\cdot5! \over 6!}={2 \over 6}={1 \over 3}$$