A) If exactly 4 boys volunteer, what is the probability that the team is all boys or no boys?
P(all four boys or no boys)=
=P(all four boys)+P(no boys)=
=(410)(44)(4−410−4)+(410)(04)(4−010−4)=
=4!(10−4)!10!1(1)+4!(10−4)!10!1⋅4!(6−4)!6!==2101+21015=1058
B) What is the probability that Student 1 and Student 2 are on the team?
P(Student1 & Student2)=(410)(11)(4−210−2)==4!(10−4)!10!1⋅2!(8−2)!8!=21028=152
C) With two teacher coaches, the team of four takes a picture (6 people in picture). What is the probability that the teachers are together in the picture?
Consider two teacher coaches as one unit.
P(teachers are together)=6!2!⋅5!=62=31
Comments