Bob randomly selected a sample of 100 children with ASD and found that only 70 of them
are in special need schools.
Q 7
What is the 90% confidence interval estimate of the proportion of children with ASD in special need schools?
(1) (0.6102; 0.7898)
(2) (0.6246; 0.7754)
(3) (0.6038; 0.7962)
(4) (0.6678; 0;8122)
(5) None of the above.
Q 8
What is the lower limit for the 95% confidence interval estimate of the proportion of children in
special need schools?
(1) 0:6102
(2) 0:6246
(3) 0:7754
(4) 0:7898
(5) None of the above.
Q 9
This time Bob want to determine whether the true proportion of ASD children in special need schools in the population is 0.75.
Assume a 5% level of significance.
Which of the following statements is incorrect?
(1) H0 : π = 0.75 against H1 : π ≠ 0.75
(2) The critical value is 1.96
(3) The value of the test statistic is 1.09
(4) The p-value is 0.2502
(5) We do not reject H0
Since it is observed that ∣z∣=1.1566<1.96=zc, it is then concluded that the null hypothesis is not rejected. Therefore, there is not enough evidence to claim that the population proportion pˉ is different than π at the α=0.05 significance level.
The p-value is p=0.2474, and since p=0.2474>0.05, it is concluded that the null hypothesis is not rejected. Therefore, there is not enough evidence to claim that the population proportion pˉ is different than π at the α=0.05 significance level.
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