Question #105330
QUESTIONS 7, 8 AND 9 ARE BASED ON THE FOLLOWING

Bob randomly selected a sample of 100 children with ASD and found that only 70 of them
are in special need schools.

Q 7

What is the 90% confidence interval estimate of the proportion of children with ASD in special need schools?
(1) (0.6102; 0.7898)
(2) (0.6246; 0.7754)
(3) (0.6038; 0.7962)
(4) (0.6678; 0;8122)
(5) None of the above.

Q 8

What is the lower limit for the 95% confidence interval estimate of the proportion of children in
special need schools?
(1) 0:6102
(2) 0:6246
(3) 0:7754
(4) 0:7898
(5) None of the above.

Q 9

This time Bob want to determine whether the true proportion of ASD children in special need schools in the population is 0.75.
Assume a 5% level of significance.

Which of the following statements is incorrect?
(1) H0 : π = 0.75 against H1 : π ≠ 0.75
(2) The critical value is 1.96
(3) The value of the test statistic is 1.09
(4) The p-value is 0.2502
(5) We do not reject H0
1
Expert's answer
2020-03-29T09:42:00-0400

Q7


CI(proportion)=(p^zα/2p^(1p^)n,p^+zα/2p^(1p^)n)CI(proportion)=(\hat{p}-z_{\alpha/2}\cdot\sqrt{{\hat{p}(1-\hat{p}) \over n}}, \hat{p}+z_{\alpha/2}\cdot\sqrt{{\hat{p}(1-\hat{p}) \over n}})

Given that n=100,p^=70/100=0.7n=100, \hat{p}=70/100=0.7

90% confidence interval: zα/2=1.645z_{\alpha/2}=1.645


CI(proportion)=(0.71.6450.7(10.7)100,0.7+1.6450.7(10.7)100)CI(proportion)=(0.7-1.645\sqrt{{0.7(1-0.7) \over 100}}, 0.7+1.645\sqrt{{0.7(1-0.7) \over 100}})

CI(proportion)=(0.6245,0.7755)CI(proportion)=(0.6245,0.7755)

(2) (0.6246; 0.7754) 


Q8

95% confidence interval: zα/2=1.96z_{\alpha/2}=1.96


p^zα/2p^(1p^)n=0.71.960.7(10.7)100\hat{p}-z_{\alpha/2}\cdot\sqrt{{\hat{p}(1-\hat{p}) \over n}}=0.7-1.96\cdot\sqrt{{0.7(1-0.7) \over 100}}\approx0.6102\approx0.6102

(1) 0:6102 


Q9

The following null and alternative hypotheses need to be tested:

H0:π=0.75H_0:\pi=0.75

H1:π0.75H_1:\pi\not=0.75

This corresponds to a two-tailed test, for which a z-test for one population proportion needs to be used.

zc=1.96z_c=1.96

The rejection region for this two-tailed test is R={z:z>1.96}R=\{z:|z|>1.96\}

The z-statistic is computed as follows:


z=pˉππ(1π)/n=0.70.750.75(10.75)/1001.1566z={\bar{p}-\pi \over \sqrt{\pi(1-\pi)/n}}={0.7-0.75\over \sqrt{0.75(1-0.75)/100}}\approx-1.1566

Since it is observed that z=1.1566<1.96=zc,|z|=1.1566<1.96=z_c, it is then concluded that the null hypothesis is not rejected. Therefore, there is not enough evidence to claim that the population proportion pˉ\bar{p} is different than π\pi at the α=0.05\alpha=0.05 significance level.

The p-value is p=0.2474,p=0.2474, and since p=0.2474>0.05,p=0.2474>0.05, it is concluded that the null hypothesis is not rejected. Therefore, there is not enough evidence to claim that the population proportion pˉ\bar{p} is different than π\pi at the α=0.05\alpha=0.05 significance level.


Which of the following statements is incorrect? 

(3) The value of the test statistic is 1.09

(4) The p-value is 0.2502 



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