Find the probability that the selected eggs are all good:
P=C104C124=1433P=\frac{C_{10}^4}{C_{12}^4}=\frac{14}{33}P=C124C104=3314
Then the probability that at least one is bad:
P‾=1−P=1933\overline{P}=1-P=\frac{19}{33}P=1−P=3319
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