Answer to Question #105111 in Statistics and Probability for lex

Question

Let a random variable follow the binomial distribution with parameters n =13, p =0.1. Compute the probability of x ≤4.

Answer 1

$\mu\text{ is the binomial random variable}, \mu\in B(n,p).\\ \mu\text{ is the number of successes in }n \text{ Bernoulli trials}.\\ P\{\mu=k\}=C_n^kp^k(1-p)^{n-k}, k=0,1,\ldots,n.\\ \text{Then }P\{\mu\leq k\}=\sum_{i=0}^kC_n^ip^i(1-p)^{n-i}.\\ \mu\in B(13,0.1).\\ P\{\mu\leq4\}=\sum_{i=0}^4C_{13}^i(0.1)^i(0.9)^{13-i}=(0.9)^{13}+13(0.1)(0.9)^{12}+78(0.1)^2(0.9)^{11}+22\cdot 13(0.1)^3(0.9)^{10}+5\cdot11\cdot13(0.1)^4(0.9)^9\approx0.9935.$