Answer to Question #345754 in Real Analysis for Roy

Question #345754

Check whether the series {Summation} n2x5/(n4+x3) , x belongs to [0, a] is uniformly convergent or not ,where a belongs to R


1
Expert's answer
2022-05-31T06:55:29-0400

ANSWER . The series n=1n2x5n4+x3\sum_{n=1}^{\infty}\frac{n^{2}x^{5}}{n^{4}+x^{3}} converges uniformly on [0,a][0,a] .

EXPLANATION.

Since a>0a>0 , then for all x[0,a],n1x\in [0,a] , n\geq 1 the inequality

0n2x5n4+x3n2a5n4=a5n20\leq \frac{n^{2}x^{5}}{n^{4}+x^{3}}\leq \frac{n^{2}a^{5}}{n^{4} }=\frac {a^{5} }{n^{2}}

is true. The series n=1a5n2=a5n=11n2\sum_{n=1}^{\infty}\frac{ a^{5}}{n^{2} }=a^{5}\cdot \sum_{n=1}^{\infty}\frac{ 1}{n^{2} } converges, because the series n=11n2\sum_{n=1}^{\infty}\frac{ 1}{n^{2} } converges ( p-series with p=2). So, by the Weierstrass M test the series n=1n2x5n4+x3\sum_{n=1}^{\infty}\frac{n^{2}x^{5}}{n^{4}+x^{3}} converges uniformly on [0,a][0,a] .



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