ANSWER . The series ∑n=1∞n4+x3n2x5 converges uniformly on [0,a] .
EXPLANATION.
Since a>0 , then for all x∈[0,a],n≥1 the inequality
0≤n4+x3n2x5≤n4n2a5=n2a5
is true. The series ∑n=1∞n2a5=a5⋅∑n=1∞n21 converges, because the series ∑n=1∞n21 converges ( p-series with p=2). So, by the Weierstrass M test the series ∑n=1∞n4+x3n2x5 converges uniformly on [0,a] .
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