Answer to Question #114849 in Real Analysis for Sheela John

Question #114849
Prove or disprove
a. Every topological space is metrizible
b. Any metric defined on X(#0) induces a topology on x
1
Expert's answer
2020-05-13T19:51:36-0400

1) Non-normal spaces cannot be metrizable. It is imply from statement that any metric space is normal (see [1]). Example of non-metrizable space: the topological vector space "\\{f\\colon\\mathbb R\\to\\mathbb R\\}" with the topology of pointwise convergence.


Particularly,  If a space is not Hausdorff it's not a metric space. Example of non Hausdorff space is infinite "X" with topology"\\tau\n= \\{ U \\subset X\\colon U = \\emptyset \\text{ or } X\\setminus U \\text{ is countable}\\}"


2) For any metric space "(X,d)" the collection of subsets "B(x,r)=\\{y\\in X\\colon d(x,y)<r\\}" form a basis for a topology on "X". It is obviously due to fact that an intersection of balls have another ball (see [2], first Lemma).


[1] https://math.stackexchange.com/questions/2872410/metric-space-is-normal-proof


[2] http://sites.millersville.edu/bikenaga/topology/notes/metric-spaces/metric-spaces.html


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS