Let be a real number. Let x~2.5 be an approximate value of with absolute error
at most 0.01. The function ( )
is evaluated at instead of . Estimate the absolute error
for example "f(x)=x^2"
then absolute error of f(x) at x = 2.5:
"|f(x+\\Delta x)-f(x)|=f(2.51)-f(2.5)=2.51^2-2.5^2=0.0501"
Comments
Leave a comment