Answer to Question #283829 in Quantitative Methods for Miko

Question #283829

Let be a real number. Let x~2.5 be an approximate value of with absolute error



at most 0.01. The function ( )





is evaluated at instead of . Estimate the absolute error


1
Expert's answer
2021-12-31T08:56:19-0500

for example f(x)=x2f(x)=x^2

then absolute error of f(x) at x = 2.5:

f(x+Δx)f(x)=f(2.51)f(2.5)=2.5122.52=0.0501|f(x+\Delta x)-f(x)|=f(2.51)-f(2.5)=2.51^2-2.5^2=0.0501


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